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230234301143131 = 3110636986747827
BaseRepresentation
bin110100010110010110011001…
…101111000001100001011011
31010012012011222022021010002111
4310112112121233001201123
5220134124322043040011
62133400102223213151
766331610416613545
oct6426263157014133
91105164868233074
10230234301143131
11673a590088807a
12219a4b497471b7
139b61003211c9c
1440bd584840695
151b93dc8824121
hexd16599bc185b

230234301143131 has 8 divisors (see below), whose sum is σ = 237884790047744. Its totient is φ = 222597785736360.

The previous prime is 230234301142961. The next prime is 230234301143183. The reversal of 230234301143131 is 131341103432032.

230234301143131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 230234301143131 - 213 = 230234301134939 is a prime.

It is a super-2 number, since 2×2302343011431312 (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 230234301143093 and 230234301143102.

It is not an unprimeable number, because it can be changed into a prime (230234301144131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3493340961 + ... + 3493406866.

It is an arithmetic number, because the mean of its divisors is an integer number (29735598755968).

Almost surely, 2230234301143131 is an apocalyptic number.

230234301143131 is a deficient number, since it is larger than the sum of its proper divisors (7650488904613).

230234301143131 is a wasteful number, since it uses less digits than its factorization.

230234301143131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6986748921.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 230234301143131 its reverse (131341103432032), we get a palindrome (361575404575163).

The spelling of 230234301143131 in words is "two hundred thirty trillion, two hundred thirty-four billion, three hundred one million, one hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 31 1063 32953 6986747827 216589182637 7426912940101 230234301143131