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23034403000441 = 73290629000063
BaseRepresentation
bin1010011110011000111010…
…11010001001000001111001
310000120001211011001021121101
411033030131122021001321
511004343424132003231
6120553505245211401
74565115656660560
oct517143532110171
9100501734037541
1023034403000441
117380920a96188
12270027ab60b61
13cb119a44c621
14598c2a258bd7
1529e29ea31661
hex14f31d689079

23034403000441 has 4 divisors (see below), whose sum is σ = 26325032000512. Its totient is φ = 19743774000372.

The previous prime is 23034403000429. The next prime is 23034403000459. The reversal of 23034403000441 is 14400030443032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23034403000441 - 27 = 23034403000313 is a prime.

It is not an unprimeable number, because it can be changed into a prime (23034403004441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1645314500025 + ... + 1645314500038.

It is an arithmetic number, because the mean of its divisors is an integer number (6581258000128).

Almost surely, 223034403000441 is an apocalyptic number.

It is an amenable number.

23034403000441 is a deficient number, since it is larger than the sum of its proper divisors (3290629000071).

23034403000441 is an equidigital number, since it uses as much as digits as its factorization.

23034403000441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3290629000070.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 23034403000441 its reverse (14400030443032), we get a palindrome (37434433443473).

The spelling of 23034403000441 in words is "twenty-three trillion, thirty-four billion, four hundred three million, four hundred forty-one", and thus it is an aban number.

Divisors: 1 7 3290629000063 23034403000441