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23044122433 = 56414085113
BaseRepresentation
bin10101011101100010…
…010110011101000001
32012110222120201012001
4111131202112131001
5334143243404213
614330351304001
71444024544263
oct253542263501
965428521161
1023044122433
119855896292
12457151b001
13223326a207
1411886d5b33
158ed1281dd
hex55d896741

23044122433 has 4 divisors (see below), whose sum is σ = 23048213188. Its totient is φ = 23040031680.

The previous prime is 23044122427. The next prime is 23044122457. The reversal of 23044122433 is 33422144032.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11948238864 + 11095883569 = 109308^2 + 105337^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23044122433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23044123433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2036916 + ... + 2048197.

It is an arithmetic number, because the mean of its divisors is an integer number (5762053297).

Almost surely, 223044122433 is an apocalyptic number.

It is an amenable number.

23044122433 is a deficient number, since it is larger than the sum of its proper divisors (4090755).

23044122433 is an equidigital number, since it uses as much as digits as its factorization.

23044122433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4090754.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 23044122433 its reverse (33422144032), we get a palindrome (56466266465).

The spelling of 23044122433 in words is "twenty-three billion, forty-four million, one hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 5641 4085113 23044122433