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23100310113 = 322229346399
BaseRepresentation
bin10101100000111000…
…101100001001100001
32012121220022100012020
4111200320230021201
5334302134410423
614340115452053
71445306252616
oct254070541141
965556270166
1023100310113
119884582991
1245882b7029
132241ab0b6a
141191d6050d
159030264e3
hex560e2c261

23100310113 has 8 divisors (see below), whose sum is σ = 30801888000. Its totient is φ = 15399469488.

The previous prime is 23100310109. The next prime is 23100310117. The reversal of 23100310113 is 31101300132.

It is an interprime number because it is at equal distance from previous prime (23100310109) and next prime (23100310117).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 23100310113 - 22 = 23100310109 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 23100310092 and 23100310101.

It is not an unprimeable number, because it can be changed into a prime (23100310117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 106513 + ... + 239886.

It is an arithmetic number, because the mean of its divisors is an integer number (3850236000).

Almost surely, 223100310113 is an apocalyptic number.

It is an amenable number.

23100310113 is a deficient number, since it is larger than the sum of its proper divisors (7701577887).

23100310113 is a wasteful number, since it uses less digits than its factorization.

23100310113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 368631.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 23100310113 its reverse (31101300132), we get a palindrome (54201610245).

The spelling of 23100310113 in words is "twenty-three billion, one hundred million, three hundred ten thousand, one hundred thirteen".

Divisors: 1 3 22229 66687 346399 1039197 7700103371 23100310113