Base | Representation |
---|---|
bin | 10101100000111011… |
… | …010101011010101001 |
3 | 2012121221121120020202 |
4 | 111200323111122221 |
5 | 334302324102213 |
6 | 14340142401545 |
7 | 1445315201144 |
oct | 254073253251 |
9 | 65557546222 |
10 | 23101003433 |
11 | 9884a06882 |
12 | 45885902b5 |
13 | 2241c94601 |
14 | 11920a105b |
15 | 903111b58 |
hex | 560ed56a9 |
23101003433 has 4 divisors (see below), whose sum is σ = 23114273988. Its totient is φ = 23087732880.
The previous prime is 23101003427. The next prime is 23101003447. The reversal of 23101003433 is 33430010132.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1665700969 + 21435302464 = 40813^2 + 146408^2 .
It is a cyclic number.
It is not a de Polignac number, because 23101003433 - 216 = 23100937897 is a prime.
It is a super-2 number, since 2×231010034332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23101003403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6632666 + ... + 6636147.
It is an arithmetic number, because the mean of its divisors is an integer number (5778568497).
Almost surely, 223101003433 is an apocalyptic number.
It is an amenable number.
23101003433 is a deficient number, since it is larger than the sum of its proper divisors (13270555).
23101003433 is a wasteful number, since it uses less digits than its factorization.
23101003433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13270554.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 23101003433 its reverse (33430010132), we get a palindrome (56531013565).
The spelling of 23101003433 in words is "twenty-three billion, one hundred one million, three thousand, four hundred thirty-three".
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