231012433 has 4 divisors (see below), whose sum is σ = 231043428. Its totient is φ = 230981440.

The previous prime is 231012427. The next prime is 231012479. The reversal of 231012433 is 334210132.

231012433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 207129664 + 23882769 = 14392^2 + 4887^2 .

It is a cyclic number.

It is not a de Polignac number, because 231012433 - 2⁵ = 231012401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 231012433.

It is not an unprimeable number, because it can be changed into a prime (231012413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3213 + ... + 21733.

It is an arithmetic number, because the mean of its divisors is an integer number (57760857).

Almost surely, 2^231012433 is an apocalyptic number.

It is an amenable number.

231012433 is a deficient number, since it is larger than the sum of its proper divisors (30995).

231012433 is a wasteful number, since it uses less digits than its factorization.

231012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30994.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 231012433 is about 15199.0931637384. The cubic root of 231012433 is about 613.5902518939.

Adding to 231012433 its reverse (334210132), we get a palindrome (565222565).

The spelling of 231012433 in words is "two hundred thirty-one million, twelve thousand, four hundred thirty-three".