Base | Representation |
---|---|
bin | 10101100000111100… |
… | …011101110110010001 |
3 | 2012121222011122012220 |
4 | 111200330131312101 |
5 | 334302413100423 |
6 | 14340153011253 |
7 | 1445320545123 |
oct | 254074356621 |
9 | 65558148186 |
10 | 23101300113 |
11 | 9885099771 |
12 | 45886b3b29 |
13 | 2242069668 |
14 | 119213b213 |
15 | 90316e9e3 |
hex | 560f1dd91 |
23101300113 has 16 divisors (see below), whose sum is σ = 30931857600. Its totient is φ = 15335925696.
The previous prime is 23101300087. The next prime is 23101300121. The reversal of 23101300113 is 31100310132.
It is not a de Polignac number, because 23101300113 - 29 = 23101299601 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23101300092 and 23101300101.
It is not an unprimeable number, because it can be changed into a prime (23101300813) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 778006 + ... + 807152.
It is an arithmetic number, because the mean of its divisors is an integer number (1933241100).
Almost surely, 223101300113 is an apocalyptic number.
It is an amenable number.
23101300113 is a deficient number, since it is larger than the sum of its proper divisors (7830557487).
23101300113 is a wasteful number, since it uses less digits than its factorization.
23101300113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30256.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 23101300113 its reverse (31100310132), we get a palindrome (54201610245).
The spelling of 23101300113 in words is "twenty-three billion, one hundred one million, three hundred thousand, one hundred thirteen".
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