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231024113 = 643359291
BaseRepresentation
bin11011100010100…
…10010111110001
3121002201020111122
431301102113301
5433120232423
634531352025
75503446455
oct1561222761
9532636448
10231024113
11109452921
1265452615
1338b2a478
142297a665
15154368c8
hexdc525f1

231024113 has 4 divisors (see below), whose sum is σ = 231384048. Its totient is φ = 230664180.

The previous prime is 231024091. The next prime is 231024137. The reversal of 231024113 is 311420132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 231024113 - 226 = 163915249 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231024091 and 231024100.

It is not an unprimeable number, because it can be changed into a prime (231024193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179003 + ... + 180288.

It is an arithmetic number, because the mean of its divisors is an integer number (57846012).

Almost surely, 2231024113 is an apocalyptic number.

It is an amenable number.

231024113 is a deficient number, since it is larger than the sum of its proper divisors (359935).

231024113 is an equidigital number, since it uses as much as digits as its factorization.

231024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 359934.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 231024113 is about 15199.4773923316. The cubic root of 231024113 is about 613.6005927707.

Adding to 231024113 its reverse (311420132), we get a palindrome (542444245).

The spelling of 231024113 in words is "two hundred thirty-one million, twenty-four thousand, one hundred thirteen".

Divisors: 1 643 359291 231024113