Base | Representation |
---|---|
bin | 110100100010000000011111… |
… | …101000010100100100100001 |
3 | 1010022000202210001122021222010 |
4 | 310202000133220110210201 |
5 | 220240241010312401040 |
6 | 2135212111445303133 |
7 | 66443520605100351 |
oct | 6442003750244441 |
9 | 1108022701567863 |
10 | 231035411450145 |
11 | 67684627756975 |
12 | 21ab4263a04aa9 |
13 | 9bbb71320a853 |
14 | 410a260428b61 |
15 | 1ba9b64335e80 |
hex | d2201fa14921 |
231035411450145 has 16 divisors (see below), whose sum is σ = 369658513683072. Its totient is φ = 123218267652480.
The previous prime is 231035411450117. The next prime is 231035411450191. The reversal of 231035411450145 is 541054114530132.
It is not a de Polignac number, because 231035411450145 - 25 = 231035411450113 is a prime.
It is a super-2 number, since 2×2310354114501452 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35557221 + ... + 41549810.
It is an arithmetic number, because the mean of its divisors is an integer number (23103657105192).
Almost surely, 2231035411450145 is an apocalyptic number.
It is an amenable number.
231035411450145 is a deficient number, since it is larger than the sum of its proper divisors (138623102232927).
231035411450145 is a wasteful number, since it uses less digits than its factorization.
231035411450145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77306792.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 231035411450145 its reverse (541054114530132), we get a palindrome (772089525980277).
The spelling of 231035411450145 in words is "two hundred thirty-one trillion, thirty-five billion, four hundred eleven million, four hundred fifty thousand, one hundred forty-five".
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