Base | Representation |
---|---|
bin | 1010100000011011001100… |
… | …01011101000011011101011 |
3 | 10000210202100102021020022211 |
4 | 11100031212023220123223 |
5 | 11012020143403113121 |
6 | 121045553331025551 |
7 | 4603143111441424 |
oct | 520154613503353 |
9 | 100722312236284 |
10 | 23104343410411 |
11 | 73a855158739a |
12 | 2711939a3b2b7 |
13 | cb79654317b3 |
14 | 59c382d9c64b |
15 | 2a0ee4cc0ce1 |
hex | 1503662e86eb |
23104343410411 has 4 divisors (see below), whose sum is σ = 23106983010552. Its totient is φ = 23101703810272.
The previous prime is 23104343410381. The next prime is 23104343410417. The reversal of 23104343410411 is 11401434340132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23104343410411 - 27 = 23104343410283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23104343410417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1319786941 + ... + 1319804446.
It is an arithmetic number, because the mean of its divisors is an integer number (5776745752638).
Almost surely, 223104343410411 is an apocalyptic number.
23104343410411 is a deficient number, since it is larger than the sum of its proper divisors (2639600141).
23104343410411 is an equidigital number, since it uses as much as digits as its factorization.
23104343410411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2639600140.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 23104343410411 its reverse (11401434340132), we get a palindrome (34505777750543).
The spelling of 23104343410411 in words is "twenty-three trillion, one hundred four billion, three hundred forty-three million, four hundred ten thousand, four hundred eleven".
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