2311201101401 has 4 divisors (see below), whose sum is σ = 2311544169012. Its totient is φ = 2310858033792.

The previous prime is 2311201101383. The next prime is 2311201101491. The reversal of 2311201101401 is 1041011021132.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1544042334025 + 767158767376 = 1242595^2 + 875876^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2311201101401 is a prime.

It is a super-2 number, since 2×2311201101401² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2311201101401.

It is not an unprimeable number, because it can be changed into a prime (2311201101491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171523700 + ... + 171537173.

It is an arithmetic number, because the mean of its divisors is an integer number (577886042253).

Almost surely, 2^{2311201101401} is an apocalyptic number.

It is an amenable number.

2311201101401 is a deficient number, since it is larger than the sum of its proper divisors (343067611).

2311201101401 is an equidigital number, since it uses as much as digits as its factorization.

2311201101401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 343067610.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 2311201101401 its reverse (1041011021132), we get a palindrome (3352212122533).

The spelling of 2311201101401 in words is "two trillion, three hundred eleven billion, two hundred one million, one hundred one thousand, four hundred one".