2311300113 has 4 divisors (see below), whose sum is σ = 3081733488. Its totient is φ = 1540866740.

The previous prime is 2311300111. The next prime is 2311300157. The reversal of 2311300113 is 3110031132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2311300113 - 2¹ = 2311300111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2311300092 and 2311300101.

It is not an unprimeable number, because it can be changed into a prime (2311300111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385216683 + ... + 385216688.

It is an arithmetic number, because the mean of its divisors is an integer number (770433372).

Almost surely, 2^2311300113 is an apocalyptic number.

It is an amenable number.

2311300113 is a deficient number, since it is larger than the sum of its proper divisors (770433375).

2311300113 is an equidigital number, since it uses as much as digits as its factorization.

2311300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 770433374.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 2311300113 is about 48075.9827044648. The cubic root of 2311300113 is about 1322.1643618745.

Adding to 2311300113 its reverse (3110031132), we get a palindrome (5421331245).

The spelling of 2311300113 in words is "two billion, three hundred eleven million, three hundred thousand, one hundred thirteen".