Base | Representation |
---|---|
bin | 10101100001101001… |
… | …001000101101010011 |
3 | 2012122210012120011112 |
4 | 111201221020231103 |
5 | 334313412310003 |
6 | 14341252003535 |
7 | 1445522225546 |
oct | 254151105523 |
9 | 65583176145 |
10 | 23113010003 |
11 | 9890767566 |
12 | 45906005ab |
13 | 22446095a5 |
14 | 119390885d |
15 | 9041d43d8 |
hex | 561a48b53 |
23113010003 has 4 divisors (see below), whose sum is σ = 23122919328. Its totient is φ = 23103100680.
The previous prime is 23113009999. The next prime is 23113010051. The reversal of 23113010003 is 30001031132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23113010003 - 22 = 23113009999 is a prime.
It is a super-2 number, since 2×231130100032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 23113010003.
It is not an unprimeable number, because it can be changed into a prime (23113010303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4951163 + ... + 4955828.
It is an arithmetic number, because the mean of its divisors is an integer number (5780729832).
Almost surely, 223113010003 is an apocalyptic number.
23113010003 is a deficient number, since it is larger than the sum of its proper divisors (9909325).
23113010003 is an equidigital number, since it uses as much as digits as its factorization.
23113010003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9909324.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 23113010003 its reverse (30001031132), we get a palindrome (53114041135).
The spelling of 23113010003 in words is "twenty-three billion, one hundred thirteen million, ten thousand, three".
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