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231144000131 = 1121013090921
BaseRepresentation
bin1101011101000101000…
…0011000101010000011
3211002121211012211000202
43113101100120222003
512241340331001011
6254104110035415
722461651404132
oct3272120305203
9732554184022
10231144000131
118a033842490
12389697a8b6b
1318a486cc415
14b28a43d919
15602c72623b
hex35d1418a83

231144000131 has 4 divisors (see below), whose sum is σ = 252157091064. Its totient is φ = 210130909200.

The previous prime is 231144000067. The next prime is 231144000149. The reversal of 231144000131 is 131000441132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 231144000131 - 26 = 231144000067 is a prime.

It is a super-2 number, since 2×2311440001312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (231141000131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10506545450 + ... + 10506545471.

It is an arithmetic number, because the mean of its divisors is an integer number (63039272766).

Almost surely, 2231144000131 is an apocalyptic number.

231144000131 is a deficient number, since it is larger than the sum of its proper divisors (21013090933).

231144000131 is a wasteful number, since it uses less digits than its factorization.

231144000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21013090932.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 231144000131 its reverse (131000441132), we get a palindrome (362144441263).

The spelling of 231144000131 in words is "two hundred thirty-one billion, one hundred forty-four million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 11 21013090921 231144000131