2312000433131 has 8 divisors (see below), whose sum is σ = 2326357597200. Its totient is φ = 2297645380512.

The previous prime is 2312000433107. The next prime is 2312000433151. The reversal of 2312000433131 is 1313340002132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2312000433131 is a prime.

It is a super-2 number, since 2×2312000433131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2312000433097 and 2312000433106.

It is not an unprimeable number, because it can be changed into a prime (2312000433151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1697945 + ... + 2739893.

It is an arithmetic number, because the mean of its divisors is an integer number (290794699650).

Almost surely, 2^{2312000433131} is an apocalyptic number.

2312000433131 is a deficient number, since it is larger than the sum of its proper divisors (14357164069).

2312000433131 is a wasteful number, since it uses less digits than its factorization.

2312000433131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1055725.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 2312000433131 its reverse (1313340002132), we get a palindrome (3625340435263).

The spelling of 2312000433131 in words is "two trillion, three hundred twelve billion, four hundred thirty-three thousand, one hundred thirty-one".