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23120024433113 = 67478972055751
BaseRepresentation
bin1010100000111000011001…
…10101111111000111011001
310000212020211020212201112102
411100130030311333013121
511012244302223324423
6121101105333453145
74604236521102656
oct520341465770731
9100766736781472
1023120024433113
117404169066893
1227149954a11b5
13cb92940a415a
1459d02d81ac2d
152a16117a9c28
hex15070cd7f1d9

23120024433113 has 8 divisors (see below), whose sum is σ = 23469999541440. Its totient is φ = 22770193446000.

The previous prime is 23120024433089. The next prime is 23120024433119. The reversal of 23120024433113 is 31133442002132.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23120024433113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23120024433119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35707013 + ... + 36348738.

It is an arithmetic number, because the mean of its divisors is an integer number (2933749942680).

Almost surely, 223120024433113 is an apocalyptic number.

It is an amenable number.

23120024433113 is a deficient number, since it is larger than the sum of its proper divisors (349975108327).

23120024433113 is an equidigital number, since it uses as much as digits as its factorization.

23120024433113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72060607.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 23120024433113 its reverse (31133442002132), we get a palindrome (54253466435245).

The spelling of 23120024433113 in words is "twenty-three trillion, one hundred twenty billion, twenty-four million, four hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 67 4789 320863 72055751 4827735317 345074991539 23120024433113