Base | Representation |
---|---|
bin | 10101100010000100… |
… | …010110010011000011 |
3 | 2012200021121222120011 |
4 | 111202010112103003 |
5 | 334322224043210 |
6 | 14342104525351 |
7 | 1445636656225 |
oct | 254204262303 |
9 | 65607558504 |
10 | 23120143555 |
11 | 989479a063 |
12 | 4592a80857 |
13 | 2245c36522 |
14 | 1194844415 |
15 | 904b42d8a |
hex | 5621164c3 |
23120143555 has 8 divisors (see below), whose sum is σ = 28095364800. Its totient is φ = 18261986496.
The previous prime is 23120143549. The next prime is 23120143561. The reversal of 23120143555 is 55534102132.
It is an interprime number because it is at equal distance from previous prime (23120143549) and next prime (23120143561).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23120143555 - 215 = 23120110787 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29265610 + ... + 29266399.
It is an arithmetic number, because the mean of its divisors is an integer number (3511920600).
Almost surely, 223120143555 is an apocalyptic number.
23120143555 is a deficient number, since it is larger than the sum of its proper divisors (4975221245).
23120143555 is an equidigital number, since it uses as much as digits as its factorization.
23120143555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58532093.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 23120143555 its reverse (55534102132), we get a palindrome (78654245687).
The spelling of 23120143555 in words is "twenty-three billion, one hundred twenty million, one hundred forty-three thousand, five hundred fifty-five".
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