Base | Representation |
---|---|
bin | 110100100100100011000110… |
… | …101100110001010000010011 |
3 | 1010022122110110100110021021012 |
4 | 310210203012230301100103 |
5 | 220301121101323244443 |
6 | 2135424225204521135 |
7 | 66462241443464405 |
oct | 6444430654612023 |
9 | 1108573410407235 |
10 | 231210013103123 |
11 | 6774168584502a |
12 | 21b220716b01ab |
13 | 9c0201a610402 |
14 | 41148a52acb75 |
15 | 1bae482b4e118 |
hex | d248c6b31413 |
231210013103123 has 4 divisors (see below), whose sum is σ = 231210431204688. Its totient is φ = 231209595001560.
The previous prime is 231210013103089. The next prime is 231210013103137. The reversal of 231210013103123 is 321301310012132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 231210013103123 - 220 = 231210012054547 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (231210033103123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208220183 + ... + 209327648.
It is an arithmetic number, because the mean of its divisors is an integer number (57802607801172).
Almost surely, 2231210013103123 is an apocalyptic number.
231210013103123 is a deficient number, since it is larger than the sum of its proper divisors (418101565).
231210013103123 is an equidigital number, since it uses as much as digits as its factorization.
231210013103123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418101564.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 231210013103123 its reverse (321301310012132), we get a palindrome (552511323115255).
The spelling of 231210013103123 in words is "two hundred thirty-one trillion, two hundred ten billion, thirteen million, one hundred three thousand, one hundred twenty-three".
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