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23121315553 = 73303045079
BaseRepresentation
bin10101100010001000…
…110100011011100001
32012200100211112020111
4111202020310123201
5334323024044203
614342150011321
71445652640150
oct254210643341
965610745214
1023121315553
11989541a656
124593346b41
132246256b0b
141194a6b597
15904cc526d
hex5622346e1

23121315553 has 4 divisors (see below), whose sum is σ = 26424360640. Its totient is φ = 19818270468.

The previous prime is 23121315551. The next prime is 23121315601. The reversal of 23121315553 is 35551312132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23121315553 - 21 = 23121315551 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23121315551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1651522533 + ... + 1651522546.

It is an arithmetic number, because the mean of its divisors is an integer number (6606090160).

Almost surely, 223121315553 is an apocalyptic number.

It is an amenable number.

23121315553 is a deficient number, since it is larger than the sum of its proper divisors (3303045087).

23121315553 is an equidigital number, since it uses as much as digits as its factorization.

23121315553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3303045086.

The product of its digits is 13500, while the sum is 31.

Adding to 23121315553 its reverse (35551312132), we get a palindrome (58672627685).

The spelling of 23121315553 in words is "twenty-three billion, one hundred twenty-one million, three hundred fifteen thousand, five hundred fifty-three".

Divisors: 1 7 3303045079 23121315553