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231233000131 = 724876196779
BaseRepresentation
bin1101011101011010001…
…1111001001011000011
3211002212000200111002001
43113112203321023003
512242031122001011
6254121005404431
722464112033300
oct3272643711303
9732760614061
10231233000131
118a07a000501
1238993569717
1318a60c91143
14b2981aa0a7
1560354567c1
hex35d68f92c3

231233000131 has 12 divisors (see below), whose sum is σ = 268993622520. Its totient is φ = 198193601760.

The previous prime is 231233000099. The next prime is 231233000161. The reversal of 231233000131 is 131000332132.

It is not a de Polignac number, because 231233000131 - 25 = 231233000099 is a prime.

It is a super-2 number, since 2×2312330001312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 231233000099 and 231233000108.

It is not an unprimeable number, because it can be changed into a prime (231233000161) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2340900 + ... + 2437678.

It is an arithmetic number, because the mean of its divisors is an integer number (22416135210).

Almost surely, 2231233000131 is an apocalyptic number.

231233000131 is a deficient number, since it is larger than the sum of its proper divisors (37760622389).

231233000131 is an equidigital number, since it uses as much as digits as its factorization.

231233000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145554 (or 145547 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 231233000131 its reverse (131000332132), we get a palindrome (362233332263).

The spelling of 231233000131 in words is "two hundred thirty-one billion, two hundred thirty-three million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 7 49 48761 96779 341327 677453 2389289 4742171 4719040819 33033285733 231233000131