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23123302113 = 37707767371
BaseRepresentation
bin10101100010010000…
…011001011011100001
32012200111120110021210
4111202100121123201
5334324031131423
614342300340333
71446005552652
oct254220313341
965614513253
1023123302113
11989655713a
124593b446a9
1322467a10b2
141195027529
15905068b93
hex5624196e1

23123302113 has 4 divisors (see below), whose sum is σ = 30831069488. Its totient is φ = 15415534740.

The previous prime is 23123302093. The next prime is 23123302127. The reversal of 23123302113 is 31120332132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 23123302113 - 214 = 23123285729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 23123302113.

It is not an unprimeable number, because it can be changed into a prime (23123302313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3853883683 + ... + 3853883688.

It is an arithmetic number, because the mean of its divisors is an integer number (7707767372).

Almost surely, 223123302113 is an apocalyptic number.

It is an amenable number.

23123302113 is a deficient number, since it is larger than the sum of its proper divisors (7707767375).

23123302113 is an equidigital number, since it uses as much as digits as its factorization.

23123302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7707767374.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 23123302113 its reverse (31120332132), we get a palindrome (54243634245).

The spelling of 23123302113 in words is "twenty-three billion, one hundred twenty-three million, three hundred two thousand, one hundred thirteen".

Divisors: 1 3 7707767371 23123302113