231300131112121 has 4 divisors (see below), whose sum is σ = 231300161788032. Its totient is φ = 231300100436212.

The previous prime is 231300131112091. The next prime is 231300131112143. The reversal of 231300131112121 is 121211131003132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-231300131112121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231300131112092 and 231300131112101.

It is not an unprimeable number, because it can be changed into a prime (231300131152121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4686756 + ... + 22012858.

It is an arithmetic number, because the mean of its divisors is an integer number (57825040447008).

Almost surely, 2^{231300131112121} is an apocalyptic number.

It is an amenable number.

231300131112121 is a deficient number, since it is larger than the sum of its proper divisors (30675911).

231300131112121 is a wasteful number, since it uses less digits than its factorization.

231300131112121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30675910.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 231300131112121 its reverse (121211131003132), we get a palindrome (352511262115253).

The spelling of 231300131112121 in words is "two hundred thirty-one trillion, three hundred billion, one hundred thirty-one million, one hundred twelve thousand, one hundred twenty-one".