Base | Representation |
---|---|
bin | 1000100111011101… |
… | …1010010001011011 |
3 | 12222012022210011101 |
4 | 2021313122101123 |
5 | 14214112112443 |
6 | 1021303412231 |
7 | 111214132153 |
oct | 21167322133 |
9 | 5865283141 |
10 | 2313004123 |
11 | a876a3261 |
12 | 546754077 |
13 | 2ab2791c1 |
14 | 17d295763 |
15 | d80de84d |
hex | 89dda45b |
2313004123 has 4 divisors (see below), whose sum is σ = 2313113440. Its totient is φ = 2312894808.
The previous prime is 2313004117. The next prime is 2313004129. The reversal of 2313004123 is 3214003132.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is an interprime number because it is at equal distance from previous prime (2313004117) and next prime (2313004129).
It is a cyclic number.
It is not a de Polignac number, because 2313004123 - 213 = 2312995931 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2313004123.
It is not an unprimeable number, because it can be changed into a prime (2313004129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11628 + ... + 69001.
It is an arithmetic number, because the mean of its divisors is an integer number (578278360).
Almost surely, 22313004123 is an apocalyptic number.
2313004123 is a deficient number, since it is larger than the sum of its proper divisors (109317).
2313004123 is an equidigital number, since it uses as much as digits as its factorization.
2313004123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109316.
The product of its (nonzero) digits is 432, while the sum is 19.
The square root of 2313004123 is about 48093.7014899041. The cubic root of 2313004123 is about 1322.4892047103.
Adding to 2313004123 its reverse (3214003132), we get a palindrome (5527007255).
Subtracting 2313004123 from its reverse (3214003132), we obtain a palindrome (900999009).
The spelling of 2313004123 in words is "two billion, three hundred thirteen million, four thousand, one hundred twenty-three".
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