Base | Representation |
---|---|
bin | 1010100001001011010000… |
… | …00110000111000001001011 |
3 | 10000220012221121010002201020 |
4 | 11100211220012013001023 |
5 | 11012431014200233120 |
6 | 121105501515323523 |
7 | 4605045364164564 |
oct | 520455006070113 |
9 | 100805847102636 |
10 | 23130145321035 |
11 | 7408492039775 |
12 | 271693aa505a3 |
13 | cba217b3972c |
14 | 59d70da4b16b |
15 | 2a1a05096640 |
hex | 15096818704b |
23130145321035 has 16 divisors (see below), whose sum is σ = 37008508688160. Its totient is φ = 12335985446400.
The previous prime is 23130145321021. The next prime is 23130145321057. The reversal of 23130145321035 is 53012354103132.
It is not a de Polignac number, because 23130145321035 - 221 = 23130143223883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23130145320987 and 23130145321005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3651820 + ... + 7719849.
It is an arithmetic number, because the mean of its divisors is an integer number (2313031793010).
Almost surely, 223130145321035 is an apocalyptic number.
23130145321035 is a deficient number, since it is larger than the sum of its proper divisors (13878363367125).
23130145321035 is a wasteful number, since it uses less digits than its factorization.
23130145321035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11507278.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 23130145321035 its reverse (53012354103132), we get a palindrome (76142499424167).
The spelling of 23130145321035 in words is "twenty-three trillion, one hundred thirty billion, one hundred forty-five million, three hundred twenty-one thousand, thirty-five".
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