Base | Representation |
---|---|
bin | 1010100001001111011111… |
… | …01111100011111001101011 |
3 | 10000220102211012102020012101 |
4 | 11100213233233203321223 |
5 | 11013000144301031103 |
6 | 121110515413354231 |
7 | 4605155650115122 |
oct | 520475757437153 |
9 | 100812735366171 |
10 | 23132421111403 |
11 | 740944a72475a |
12 | 2717275038977 |
13 | cba4bb486356 |
14 | 59d887db6ab9 |
15 | 2a1ad9c84a1d |
hex | 1509efbe3e6b |
23132421111403 has 4 divisors (see below), whose sum is σ = 23261652514440. Its totient is φ = 23003189708368.
The previous prime is 23132421111383. The next prime is 23132421111407. The reversal of 23132421111403 is 30411112423132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23132421111403 - 233 = 23123831176811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23132421111407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64615701250 + ... + 64615701607.
It is an arithmetic number, because the mean of its divisors is an integer number (5815413128610).
Almost surely, 223132421111403 is an apocalyptic number.
23132421111403 is a deficient number, since it is larger than the sum of its proper divisors (129231403037).
23132421111403 is a wasteful number, since it uses less digits than its factorization.
23132421111403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129231403036.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 23132421111403 its reverse (30411112423132), we get a palindrome (53543533534535).
The spelling of 23132421111403 in words is "twenty-three trillion, one hundred thirty-two billion, four hundred twenty-one million, one hundred eleven thousand, four hundred three".
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