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231331100113 = 458350475911
BaseRepresentation
bin1101011101110001101…
…0000111010111010001
3211010002212021110221201
43113130122013113101
512242231230200423
6254134432151201
722466412623131
oct3273432072721
9733085243851
10231331100113
118a11a414473
1238a00398501
1318a783bab79
14b2a7224ac1
15603dd832ad
hex35dc6875d1

231331100113 has 4 divisors (see below), whose sum is σ = 231381580608. Its totient is φ = 231280619620.

The previous prime is 231331100087. The next prime is 231331100149. The reversal of 231331100113 is 311001133132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-231331100113 is a prime.

It is a super-2 number, since 2×2313311001132 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (231331100813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25233373 + ... + 25242538.

It is an arithmetic number, because the mean of its divisors is an integer number (57845395152).

Almost surely, 2231331100113 is an apocalyptic number.

It is an amenable number.

231331100113 is a deficient number, since it is larger than the sum of its proper divisors (50480495).

231331100113 is an equidigital number, since it uses as much as digits as its factorization.

231331100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50480494.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 231331100113 its reverse (311001133132), we get a palindrome (542332233245).

The spelling of 231331100113 in words is "two hundred thirty-one billion, three hundred thirty-one million, one hundred thousand, one hundred thirteen".

Divisors: 1 4583 50475911 231331100113