Base | Representation |
---|---|
bin | 1010100001010011001101… |
… | …00010001101011001010011 |
3 | 10000220121222002120112122202 |
4 | 11100221212202031121103 |
5 | 11013013240002200201 |
6 | 121111445250153415 |
7 | 4605256230205502 |
oct | 520514642153123 |
9 | 100817862515582 |
10 | 23134414100051 |
11 | 740a282712611 |
12 | 271773058286b |
13 | cba748347287 |
14 | 59d9d6968839 |
15 | 2a1ba4c0ec6b |
hex | 150a6688d653 |
23134414100051 has 16 divisors (see below), whose sum is σ = 23385562358400. Its totient is φ = 22883708467200.
The previous prime is 23134414100027. The next prime is 23134414100053. The reversal of 23134414100051 is 15000141443132.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23134414100051 is a prime.
It is a super-2 number, since 2×231344141000512 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23134414099987 and 23134414100023.
It is not an unprimeable number, because it can be changed into a prime (23134414100053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 551415491 + ... + 551457443.
It is an arithmetic number, because the mean of its divisors is an integer number (1461597647400).
Almost surely, 223134414100051 is an apocalyptic number.
23134414100051 is a deficient number, since it is larger than the sum of its proper divisors (251148258349).
23134414100051 is a wasteful number, since it uses less digits than its factorization.
23134414100051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47086.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 23134414100051 its reverse (15000141443132), we get a palindrome (38134555543183).
The spelling of 23134414100051 in words is "twenty-three trillion, one hundred thirty-four billion, four hundred fourteen million, one hundred thousand, fifty-one".
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