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2314121534003 = 19131209681931
BaseRepresentation
bin100001101011001100011…
…001000101101000110011
322012020011002221010121002
4201223030121011220303
5300403310103042003
64531032011352215
7326122042326446
oct41531431055063
98166132833532
102314121534003
11812460305644
123145aa75266b
1313a2b3c15056
148000b2a365d
15402e02c9a88
hex21acc645a33

2314121534003 has 4 divisors (see below), whose sum is σ = 2315331217848. Its totient is φ = 2312911850160.

The previous prime is 2314121533987. The next prime is 2314121534027. The reversal of 2314121534003 is 3004351214132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2314121534003 - 24 = 2314121533987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2314121534063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604839053 + ... + 604842878.

It is an arithmetic number, because the mean of its divisors is an integer number (578832804462).

Almost surely, 22314121534003 is an apocalyptic number.

2314121534003 is a deficient number, since it is larger than the sum of its proper divisors (1209683845).

2314121534003 is a wasteful number, since it uses less digits than its factorization.

2314121534003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1209683844.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 2314121534003 its reverse (3004351214132), we get a palindrome (5318472748135).

The spelling of 2314121534003 in words is "two trillion, three hundred fourteen billion, one hundred twenty-one million, five hundred thirty-four thousand, three".

Divisors: 1 1913 1209681931 2314121534003