Base | Representation |
---|---|
bin | 10101100011100000… |
… | …111001000110000011 |
3 | 2012201222021111201101 |
4 | 111203200321012003 |
5 | 334344431401311 |
6 | 14344332515231 |
7 | 1446353116360 |
oct | 254340710603 |
9 | 65658244641 |
10 | 23144403331 |
11 | 98a7459865 |
12 | 459b01bb17 |
13 | 224ac7b81a |
14 | 1197b5b467 |
15 | 906d35ec1 |
hex | 563839183 |
23144403331 has 4 divisors (see below), whose sum is σ = 26450746672. Its totient is φ = 19838059992.
The previous prime is 23144403323. The next prime is 23144403341. The reversal of 23144403331 is 13330444132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23144403331 - 23 = 23144403323 is a prime.
It is a super-2 number, since 2×231444033312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 23144403331.
It is not an unprimeable number, because it can be changed into a prime (23144403301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1653171660 + ... + 1653171673.
It is an arithmetic number, because the mean of its divisors is an integer number (6612686668).
Almost surely, 223144403331 is an apocalyptic number.
23144403331 is a deficient number, since it is larger than the sum of its proper divisors (3306343341).
23144403331 is an equidigital number, since it uses as much as digits as its factorization.
23144403331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3306343340.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 23144403331 its reverse (13330444132), we get a palindrome (36474847463).
The spelling of 23144403331 in words is "twenty-three billion, one hundred forty-four million, four hundred three thousand, three hundred thirty-one".
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