Base | Representation |
---|---|
bin | 100001101100000111111… |
… | …010000100010100110011 |
3 | 22012022201200210020122001 |
4 | 201230013322010110303 |
5 | 300412331212110443 |
6 | 4531315040554431 |
7 | 326155555415440 |
oct | 41540772042463 |
9 | 8168650706561 |
10 | 2315120035123 |
11 | 8129229a5285 |
12 | 314829022a17 |
13 | 13a412a48c0c |
14 | 800a3b409c7 |
15 | 4034ccb1d4d |
hex | 21b07e84533 |
2315120035123 has 4 divisors (see below), whose sum is σ = 2645851468720. Its totient is φ = 1984388601528.
The previous prime is 2315120035051. The next prime is 2315120035133. The reversal of 2315120035123 is 3215300215132.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2315120035123 - 217 = 2315119904051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2315120035091 and 2315120035100.
It is not an unprimeable number, because it can be changed into a prime (2315120035133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165365716788 + ... + 165365716801.
It is an arithmetic number, because the mean of its divisors is an integer number (661462867180).
Almost surely, 22315120035123 is an apocalyptic number.
2315120035123 is a deficient number, since it is larger than the sum of its proper divisors (330731433597).
2315120035123 is an equidigital number, since it uses as much as digits as its factorization.
2315120035123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 330731433596.
The product of its (nonzero) digits is 5400, while the sum is 28.
The spelling of 2315120035123 in words is "two trillion, three hundred fifteen billion, one hundred twenty million, thirty-five thousand, one hundred twenty-three".
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