Base | Representation |
---|---|
bin | 1101100000010100011… |
… | …1001011000100111001 |
3 | 211011212110021102002110 |
4 | 3120011013023010321 |
5 | 12300131041003231 |
6 | 254330305122533 |
7 | 22522344315156 |
oct | 3300507130471 |
9 | 734773242073 |
10 | 232014000441 |
11 | 8a43a944603 |
12 | 38b71029449 |
13 | 18b56a20cc2 |
14 | b32dbcb22d |
15 | 607dcc9046 |
hex | 36051cb139 |
232014000441 has 4 divisors (see below), whose sum is σ = 309352000592. Its totient is φ = 154676000292.
The previous prime is 232014000437. The next prime is 232014000473. The reversal of 232014000441 is 144000410232.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 232014000441 - 22 = 232014000437 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (232014000541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38669000071 + ... + 38669000076.
It is an arithmetic number, because the mean of its divisors is an integer number (77338000148).
Almost surely, 2232014000441 is an apocalyptic number.
It is an amenable number.
232014000441 is a deficient number, since it is larger than the sum of its proper divisors (77338000151).
232014000441 is an equidigital number, since it uses as much as digits as its factorization.
232014000441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77338000150.
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 232014000441 its reverse (144000410232), we get a palindrome (376014410673).
The spelling of 232014000441 in words is "two hundred thirty-two billion, fourteen million, four hundred forty-one", and thus it is an aban number.
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