Base | Representation |
---|---|
bin | 10101100111000000… |
… | …011101011110000001 |
3 | 2012220001120001112210 |
4 | 111213000131132001 |
5 | 340004432313213 |
6 | 14354225012333 |
7 | 1450664222511 |
oct | 254700353601 |
9 | 65801501483 |
10 | 23203010433 |
11 | 9927549189 |
12 | 45b67840a9 |
13 | 225a15b795 |
14 | 11a1855841 |
15 | 90c0610c3 |
hex | 56701d781 |
23203010433 has 4 divisors (see below), whose sum is σ = 30937347248. Its totient is φ = 15468673620.
The previous prime is 23203010401. The next prime is 23203010497. The reversal of 23203010433 is 33401030232.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 23203010433 - 25 = 23203010401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23203010833) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3867168403 + ... + 3867168408.
It is an arithmetic number, because the mean of its divisors is an integer number (7734336812).
Almost surely, 223203010433 is an apocalyptic number.
It is an amenable number.
23203010433 is a deficient number, since it is larger than the sum of its proper divisors (7734336815).
23203010433 is an equidigital number, since it uses as much as digits as its factorization.
23203010433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7734336814.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 23203010433 its reverse (33401030232), we get a palindrome (56604040665).
The spelling of 23203010433 in words is "twenty-three billion, two hundred three million, ten thousand, four hundred thirty-three".
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