Base | Representation |
---|---|
bin | 110100110001100010010010… |
… | …000111110100111100010001 |
3 | 1010102210210002012021111201101 |
4 | 310301202102013310330101 |
5 | 220410231341423414413 |
6 | 2141350224221504401 |
7 | 66613564633605562 |
oct | 6461422207647421 |
9 | 1112723065244641 |
10 | 232102484201233 |
11 | 67a56124483458 |
12 | 22047024412101 |
13 | 9c6822a32c289 |
14 | 4145b6a7bc169 |
15 | 1bc77b91d9edd |
hex | d318921f4f11 |
232102484201233 has 4 divisors (see below), whose sum is σ = 234355906378048. Its totient is φ = 229849062024420.
The previous prime is 232102484201221. The next prime is 232102484201279. The reversal of 232102484201233 is 332102484201232.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-232102484201233 is a prime.
It is a super-2 number, since 2×2321024842012332 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 232102484201192 and 232102484201201.
It is not an unprimeable number, because it can be changed into a prime (232102484201633) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1126711088253 + ... + 1126711088458.
It is an arithmetic number, because the mean of its divisors is an integer number (58588976594512).
Almost surely, 2232102484201233 is an apocalyptic number.
It is an amenable number.
232102484201233 is a deficient number, since it is larger than the sum of its proper divisors (2253422176815).
232102484201233 is a wasteful number, since it uses less digits than its factorization.
232102484201233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2253422176814.
The product of its (nonzero) digits is 110592, while the sum is 37.
Subtracting 232102484201233 from its reverse (332102484201232), we obtain a palindrome (99999999999999).
The spelling of 232102484201233 in words is "two hundred thirty-two trillion, one hundred two billion, four hundred eighty-four million, two hundred one thousand, two hundred thirty-three".
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