Base | Representation |
---|---|
bin | 1010100011100010000010… |
… | …10111101111101100101011 |
3 | 10001011221220110122110120011 |
4 | 11101301001113233230223 |
5 | 11020242313100330212 |
6 | 121211010535312351 |
7 | 4613642460536005 |
oct | 521610127575453 |
9 | 101157813573504 |
10 | 23211100011307 |
11 | 743985493177a |
12 | 272a57251b6b7 |
13 | cc4a499a6120 |
14 | 5a35cd4db375 |
15 | 2a3b922964a7 |
hex | 151c415efb2b |
23211100011307 has 8 divisors (see below), whose sum is σ = 24996872442080. Its totient is φ = 21425370894720.
The previous prime is 23211100011293. The next prime is 23211100011313. The reversal of 23211100011307 is 70311000111232.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 23211100011307 - 227 = 23210965793579 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23211100017307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9711294 + ... + 11863027.
It is an arithmetic number, because the mean of its divisors is an integer number (3124609055260).
Almost surely, 223211100011307 is an apocalyptic number.
23211100011307 is a deficient number, since it is larger than the sum of its proper divisors (1785772430773).
23211100011307 is a wasteful number, since it uses less digits than its factorization.
23211100011307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21657093.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 23211100011307 its reverse (70311000111232), we get a palindrome (93522100122539).
The spelling of 23211100011307 in words is "twenty-three trillion, two hundred eleven billion, one hundred million, eleven thousand, three hundred seven".
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