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2325120050035 = 5465024010007
BaseRepresentation
bin100001110101011011111…
…101000110001101110011
322020021112121120122012201
4201311123331012031303
5301043321213100120
64540051224004031
7326661433222036
oct41653375061563
98207477518181
102325120050035
1181709471a512
1231675a000617
1313b3477400c3
1480771ca901d
1540735b7440a
hex21d5bf46373

2325120050035 has 4 divisors (see below), whose sum is σ = 2790144060048. Its totient is φ = 1860096040024.

The previous prime is 2325120050009. The next prime is 2325120050051. The reversal of 2325120050035 is 5300500215232.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2325120050035 - 219 = 2325119525747 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2325120049985 and 2325120050012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232512004999 + ... + 232512005008.

It is an arithmetic number, because the mean of its divisors is an integer number (697536015012).

Almost surely, 22325120050035 is an apocalyptic number.

2325120050035 is a deficient number, since it is larger than the sum of its proper divisors (465024010013).

2325120050035 is an equidigital number, since it uses as much as digits as its factorization.

2325120050035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465024010012.

The product of its (nonzero) digits is 9000, while the sum is 28.

Adding to 2325120050035 its reverse (5300500215232), we get a palindrome (7625620265267).

The spelling of 2325120050035 in words is "two trillion, three hundred twenty-five billion, one hundred twenty million, fifty thousand, thirty-five".

Divisors: 1 5 465024010007 2325120050035