Base | Representation |
---|---|
bin | 100001110101011011111… |
… | …101000110001101110011 |
3 | 22020021112121120122012201 |
4 | 201311123331012031303 |
5 | 301043321213100120 |
6 | 4540051224004031 |
7 | 326661433222036 |
oct | 41653375061563 |
9 | 8207477518181 |
10 | 2325120050035 |
11 | 81709471a512 |
12 | 31675a000617 |
13 | 13b3477400c3 |
14 | 80771ca901d |
15 | 40735b7440a |
hex | 21d5bf46373 |
2325120050035 has 4 divisors (see below), whose sum is σ = 2790144060048. Its totient is φ = 1860096040024.
The previous prime is 2325120050009. The next prime is 2325120050051. The reversal of 2325120050035 is 5300500215232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2325120050035 - 219 = 2325119525747 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2325120049985 and 2325120050012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232512004999 + ... + 232512005008.
It is an arithmetic number, because the mean of its divisors is an integer number (697536015012).
Almost surely, 22325120050035 is an apocalyptic number.
2325120050035 is a deficient number, since it is larger than the sum of its proper divisors (465024010013).
2325120050035 is an equidigital number, since it uses as much as digits as its factorization.
2325120050035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 465024010012.
The product of its (nonzero) digits is 9000, while the sum is 28.
Adding to 2325120050035 its reverse (5300500215232), we get a palindrome (7625620265267).
The spelling of 2325120050035 in words is "two trillion, three hundred twenty-five billion, one hundred twenty million, fifty thousand, thirty-five".
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