Base | Representation |
---|---|
bin | 100001110101100000111… |
… | …101100011000000010011 |
3 | 22020021202110122111000222 |
4 | 201311200331203000103 |
5 | 301044004214212120 |
6 | 4540103424303255 |
7 | 326663503232462 |
oct | 41654075430023 |
9 | 8207673574028 |
10 | 2325204054035 |
11 | 817128085a05 |
12 | 316782171b2b |
13 | 13b35bc72b05 |
14 | 8077d0d49d9 |
15 | 4073d219525 |
hex | 21d60f63013 |
2325204054035 has 4 divisors (see below), whose sum is σ = 2790244864848. Its totient is φ = 1860163243224.
The previous prime is 2325204053999. The next prime is 2325204054077. The reversal of 2325204054035 is 5304504025232.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2325204054035 - 26 = 2325204053971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2325204053986 and 2325204054004.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232520405399 + ... + 232520405408.
It is an arithmetic number, because the mean of its divisors is an integer number (697561216212).
Almost surely, 22325204054035 is an apocalyptic number.
2325204054035 is a deficient number, since it is larger than the sum of its proper divisors (465040810813).
2325204054035 is an equidigital number, since it uses as much as digits as its factorization.
2325204054035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 465040810812.
The product of its (nonzero) digits is 144000, while the sum is 35.
Adding to 2325204054035 its reverse (5304504025232), we get a palindrome (7629708079267).
The spelling of 2325204054035 in words is "two trillion, three hundred twenty-five billion, two hundred four million, fifty-four thousand, thirty-five".
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