Base | Representation |
---|---|
bin | 100001110110100100110… |
… | …000011000010111111001 |
3 | 22020101200201212100111212 |
4 | 201312210300120113321 |
5 | 301103321403001210 |
6 | 4540412334532505 |
7 | 330033624042362 |
oct | 41664460302771 |
9 | 8211621770455 |
10 | 2326341453305 |
11 | 817661114901 |
12 | 316a3b067135 |
13 | 13b4b07b962c |
14 | 8084a1aab69 |
15 | 407a7edb805 |
hex | 21da4c185f9 |
2326341453305 has 4 divisors (see below), whose sum is σ = 2791609743972. Its totient is φ = 1861073162640.
The previous prime is 2326341453277. The next prime is 2326341453307. The reversal of 2326341453305 is 5033541436232.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1405637875216 + 920703578089 = 1185596^2 + 959533^2 .
It is not a de Polignac number, because 2326341453305 - 232 = 2322046486009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2326341453307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232634145326 + ... + 232634145335.
It is an arithmetic number, because the mean of its divisors is an integer number (697902435993).
Almost surely, 22326341453305 is an apocalyptic number.
It is an amenable number.
2326341453305 is a deficient number, since it is larger than the sum of its proper divisors (465268290667).
2326341453305 is an equidigital number, since it uses as much as digits as its factorization.
2326341453305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 465268290666.
The product of its (nonzero) digits is 777600, while the sum is 41.
Adding to 2326341453305 its reverse (5033541436232), we get a palindrome (7359882889537).
The spelling of 2326341453305 in words is "two trillion, three hundred twenty-six billion, three hundred forty-one million, four hundred fifty-three thousand, three hundred five".
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