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23304002131 = 48134841887
BaseRepresentation
bin10101101101000001…
…101101101001010011
32020011002120222010001
4111231001231221103
5340211311032011
614412233350431
71453331515114
oct255501555123
966132528101
1023304002131
1199795577a3
124624568417
13227505b797
1411b102420b
15915d5e7c1
hex56d06da53

23304002131 has 4 divisors (see below), whose sum is σ = 23308848832. Its totient is φ = 23299155432.

The previous prime is 23304002087. The next prime is 23304002143. The reversal of 23304002131 is 13120040332.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23304002131 - 215 = 23303969363 is a prime.

It is a super-2 number, since 2×233040021312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23304002099 and 23304002108.

It is not an unprimeable number, because it can be changed into a prime (23304002171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2416131 + ... + 2425756.

It is an arithmetic number, because the mean of its divisors is an integer number (5827212208).

Almost surely, 223304002131 is an apocalyptic number.

23304002131 is a deficient number, since it is larger than the sum of its proper divisors (4846701).

23304002131 is an equidigital number, since it uses as much as digits as its factorization.

23304002131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4846700.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 23304002131 its reverse (13120040332), we get a palindrome (36424042463).

The spelling of 23304002131 in words is "twenty-three billion, three hundred four million, two thousand, one hundred thirty-one".

Divisors: 1 4813 4841887 23304002131