Base | Representation |
---|---|
bin | 100001111010111010011… |
… | …111111110110000011011 |
3 | 22020211201111001000220002 |
4 | 201322322133332300123 |
5 | 301142342303020443 |
6 | 4542502553523215 |
7 | 330260245311362 |
oct | 41727237766033 |
9 | 8224644030802 |
10 | 2331001220123 |
11 | 819632468664 |
12 | 31791b71350b |
13 | 13ba740016c4 |
14 | 80b6cdc47d9 |
15 | 4097c1382b8 |
hex | 21eba7fec1b |
2331001220123 has 4 divisors (see below), whose sum is σ = 2346438314448. Its totient is φ = 2315564125800.
The previous prime is 2331001220113. The next prime is 2331001220131. The reversal of 2331001220123 is 3210221001332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2331001220123 - 220 = 2331000171547 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2331001220095 and 2331001220104.
It is not an unprimeable number, because it can be changed into a prime (2331001220113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7718546936 + ... + 7718547237.
It is an arithmetic number, because the mean of its divisors is an integer number (586609578612).
Almost surely, 22331001220123 is an apocalyptic number.
2331001220123 is a deficient number, since it is larger than the sum of its proper divisors (15437094325).
2331001220123 is a wasteful number, since it uses less digits than its factorization.
2331001220123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15437094324.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2331001220123 its reverse (3210221001332), we get a palindrome (5541222221455).
The spelling of 2331001220123 in words is "two trillion, three hundred thirty-one billion, one million, two hundred twenty thousand, one hundred twenty-three".
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