2331104011331 has 4 divisors (see below), whose sum is σ = 2331641260200. Its totient is φ = 2330566762464.

The previous prime is 2331104011303. The next prime is 2331104011351. The reversal of 2331104011331 is 1331104011332.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2331104011331 - 2⁶ = 2331104011267 is a prime.

It is a super-3 number, since 3×2331104011331³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2331104011297 and 2331104011306.

It is not an unprimeable number, because it can be changed into a prime (2331104011351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268617926 + ... + 268626603.

It is an arithmetic number, because the mean of its divisors is an integer number (582910315050).

Almost surely, 2^{2331104011331} is an apocalyptic number.

2331104011331 is a deficient number, since it is larger than the sum of its proper divisors (537248869).

2331104011331 is an equidigital number, since it uses as much as digits as its factorization.

2331104011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 537248868.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 2331104011331 its reverse (1331104011332), we get a palindrome (3662208022663).

Subtracting from 2331104011331 its reverse (1331104011332), we obtain a palindrome (999999999999).

The spelling of 2331104011331 in words is "two trillion, three hundred thirty-one billion, one hundred four million, eleven thousand, three hundred thirty-one".