Base | Representation |
---|---|
bin | 1101100100110010110… |
… | …1111110100011110001 |
3 | 211021222011211112220020 |
4 | 3121030231332203301 |
5 | 12310111112330441 |
6 | 255045422234053 |
7 | 22564202545020 |
oct | 3311455764361 |
9 | 737864745806 |
10 | 233215355121 |
11 | 8a9a6a96111 |
12 | 39247425929 |
13 | 18cb889ac68 |
14 | b4055908b7 |
15 | 60ee4d0e66 |
hex | 364cb7e8f1 |
233215355121 has 16 divisors (see below), whose sum is σ = 355410701184. Its totient is φ = 133252821504.
The previous prime is 233215355099. The next prime is 233215355221. The reversal of 233215355121 is 121553512332.
It is not a de Polignac number, because 233215355121 - 25 = 233215355089 is a prime.
It is a super-3 number, since 3×2332153551213 (a number of 35 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (233215355221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324786 + ... + 756251.
It is an arithmetic number, because the mean of its divisors is an integer number (22213168824).
Almost surely, 2233215355121 is an apocalyptic number.
233215355121 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
233215355121 is a deficient number, since it is larger than the sum of its proper divisors (122195346063).
233215355121 is a wasteful number, since it uses less digits than its factorization.
233215355121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1091320.
The product of its digits is 27000, while the sum is 33.
Adding to 233215355121 its reverse (121553512332), we get a palindrome (354768867453).
The spelling of 233215355121 in words is "two hundred thirty-three billion, two hundred fifteen million, three hundred fifty-five thousand, one hundred twenty-one".
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