Base | Representation |
---|---|
bin | 1101100100110110101… |
… | …0011110000111001001 |
3 | 211022000021200012211010 |
4 | 3121031222132013021 |
5 | 12310124142304001 |
6 | 255051150154133 |
7 | 22564454412633 |
oct | 3311552360711 |
9 | 738007605733 |
10 | 233231213001 |
11 | 8aa04a373a6 |
12 | 392507b2949 |
13 | 18cbbc60c17 |
14 | b40771ba53 |
15 | 6100ab48d6 |
hex | 364da9e1c9 |
233231213001 has 4 divisors (see below), whose sum is σ = 310974950672. Its totient is φ = 155487475332.
The previous prime is 233231212987. The next prime is 233231213021. The reversal of 233231213001 is 100312132332.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 233231213001 - 210 = 233231211977 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (233231213021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38871868831 + ... + 38871868836.
It is an arithmetic number, because the mean of its divisors is an integer number (77743737668).
Almost surely, 2233231213001 is an apocalyptic number.
It is an amenable number.
233231213001 is a deficient number, since it is larger than the sum of its proper divisors (77743737671).
233231213001 is an equidigital number, since it uses as much as digits as its factorization.
233231213001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77743737670.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 233231213001 its reverse (100312132332), we get a palindrome (333543345333).
The spelling of 233231213001 in words is "two hundred thirty-three billion, two hundred thirty-one million, two hundred thirteen thousand, one".
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