Base | Representation |
---|---|
bin | 1101100101100001100… |
… | …0010011011101000011 |
3 | 211022110210222100101201 |
4 | 3121120120103131003 |
5 | 12311011204001011 |
6 | 255121051442031 |
7 | 22602066523441 |
oct | 3313030233503 |
9 | 738423870351 |
10 | 233411000131 |
11 | 8aa97474101 |
12 | 392a0a56317 |
13 | 1901a28bc3a |
14 | b42355bb91 |
15 | 6111779cc1 |
hex | 3658613743 |
233411000131 has 4 divisors (see below), whose sum is σ = 240940387264. Its totient is φ = 225881613000.
The previous prime is 233411000089. The next prime is 233411000239. The reversal of 233411000131 is 131000114332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-233411000131 is a prime.
It is a super-2 number, since 2×2334110001312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 233411000099 and 233411000108.
It is not an unprimeable number, because it can be changed into a prime (233411000731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3764693520 + ... + 3764693581.
It is an arithmetic number, because the mean of its divisors is an integer number (60235096816).
Almost surely, 2233411000131 is an apocalyptic number.
233411000131 is a deficient number, since it is larger than the sum of its proper divisors (7529387133).
233411000131 is an equidigital number, since it uses as much as digits as its factorization.
233411000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7529387132.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 233411000131 its reverse (131000114332), we get a palindrome (364411114463).
The spelling of 233411000131 in words is "two hundred thirty-three billion, four hundred eleven million, one hundred thirty-one", and thus it is an aban number.
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