Base | Representation |
---|---|
bin | 100001111110000001101… |
… | …000000110000110001011 |
3 | 22021011100022022220121120 |
4 | 201332001220012012023 |
5 | 301221213023411243 |
6 | 4544214254410323 |
7 | 330436112504265 |
oct | 41760150060613 |
9 | 8234308286546 |
10 | 2334342013323 |
11 | 81aa97234a81 |
12 | 3184b25009a3 |
13 | 13c187197608 |
14 | 80da897cb35 |
15 | 40ac5597c83 |
hex | 21f81a0618b |
2334342013323 has 4 divisors (see below), whose sum is σ = 3112456017768. Its totient is φ = 1556228008880.
The previous prime is 2334342013313. The next prime is 2334342013327. The reversal of 2334342013323 is 3233102434332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2334342013323 - 214 = 2334341996939 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2334342013327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389057002218 + ... + 389057002223.
It is an arithmetic number, because the mean of its divisors is an integer number (778114004442).
Almost surely, 22334342013323 is an apocalyptic number.
2334342013323 is a deficient number, since it is larger than the sum of its proper divisors (778114004445).
2334342013323 is an equidigital number, since it uses as much as digits as its factorization.
2334342013323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 778114004444.
The product of its (nonzero) digits is 93312, while the sum is 33.
Adding to 2334342013323 its reverse (3233102434332), we get a palindrome (5567444447655).
The spelling of 2334342013323 in words is "two trillion, three hundred thirty-four billion, three hundred forty-two million, thirteen thousand, three hundred twenty-three".
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