Base | Representation |
---|---|
bin | 1010101000000000101111… |
… | …01111100001111110000011 |
3 | 10001201200012110001200112011 |
4 | 11110000113233201332003 |
5 | 11030303030212113430 |
6 | 121405424152113351 |
7 | 4631031662506024 |
oct | 524002757417603 |
9 | 101650173050464 |
10 | 23365020426115 |
11 | 749905a9a6565 |
12 | 275436a095857 |
13 | 1006409530654 |
14 | 5aac31806c4b |
15 | 2a7ba012a22a |
hex | 154017be1f83 |
23365020426115 has 4 divisors (see below), whose sum is σ = 28038024511344. Its totient is φ = 18692016340888.
The previous prime is 23365020426113. The next prime is 23365020426119. The reversal of 23365020426115 is 51162402056332.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23365020426115 - 21 = 23365020426113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23365020426113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2336502042607 + ... + 2336502042616.
It is an arithmetic number, because the mean of its divisors is an integer number (7009506127836).
Almost surely, 223365020426115 is an apocalyptic number.
23365020426115 is a deficient number, since it is larger than the sum of its proper divisors (4673004085229).
23365020426115 is an equidigital number, since it uses as much as digits as its factorization.
23365020426115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4673004085228.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 23365020426115 in words is "twenty-three trillion, three hundred sixty-five billion, twenty million, four hundred twenty-six thousand, one hundred fifteen".
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