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23400150412513 = 73919852992761
BaseRepresentation
bin1010101001000010001011…
…01001110010110011100001
310001212000212201022220021111
411110201011221302303201
511031342002001200023
6121433514121423321
74633414353455320
oct524410551626341
9101760781286244
1023400150412513
117501a4795a276
12275b13303ab41
131009817666854
145ac8052ac0b7
152a8a592d500d
hex154845a72ce1

23400150412513 has 8 divisors (see below), whose sum is σ = 26749853016320. Its totient is φ = 20052153802080.

The previous prime is 23400150412501. The next prime is 23400150412517. The reversal of 23400150412513 is 31521405100432.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 23400150412513 - 213 = 23400150404321 is a prime.

It is not an unprimeable number, because it can be changed into a prime (23400150412517) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 426468948 + ... + 426523813.

It is an arithmetic number, because the mean of its divisors is an integer number (3343731627040).

Almost surely, 223400150412513 is an apocalyptic number.

It is an amenable number.

23400150412513 is a deficient number, since it is larger than the sum of its proper divisors (3349702603807).

23400150412513 is an equidigital number, since it uses as much as digits as its factorization.

23400150412513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 852996687.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 23400150412513 its reverse (31521405100432), we get a palindrome (54921555512945).

The spelling of 23400150412513 in words is "twenty-three trillion, four hundred billion, one hundred fifty million, four hundred twelve thousand, five hundred thirteen".

Divisors: 1 7 3919 27433 852992761 5970949327 3342878630359 23400150412513