Base | Representation |
---|---|
bin | 1010101001000010001011… |
… | …01001110010110011100001 |
3 | 10001212000212201022220021111 |
4 | 11110201011221302303201 |
5 | 11031342002001200023 |
6 | 121433514121423321 |
7 | 4633414353455320 |
oct | 524410551626341 |
9 | 101760781286244 |
10 | 23400150412513 |
11 | 7501a4795a276 |
12 | 275b13303ab41 |
13 | 1009817666854 |
14 | 5ac8052ac0b7 |
15 | 2a8a592d500d |
hex | 154845a72ce1 |
23400150412513 has 8 divisors (see below), whose sum is σ = 26749853016320. Its totient is φ = 20052153802080.
The previous prime is 23400150412501. The next prime is 23400150412517. The reversal of 23400150412513 is 31521405100432.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23400150412513 - 213 = 23400150404321 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23400150412517) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 426468948 + ... + 426523813.
It is an arithmetic number, because the mean of its divisors is an integer number (3343731627040).
Almost surely, 223400150412513 is an apocalyptic number.
It is an amenable number.
23400150412513 is a deficient number, since it is larger than the sum of its proper divisors (3349702603807).
23400150412513 is an equidigital number, since it uses as much as digits as its factorization.
23400150412513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 852996687.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 23400150412513 its reverse (31521405100432), we get a palindrome (54921555512945).
The spelling of 23400150412513 in words is "twenty-three trillion, four hundred billion, one hundred fifty million, four hundred twelve thousand, five hundred thirteen".
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