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23400537611137 = 171540713641391
BaseRepresentation
bin1010101001000010111001…
…01110110101101110000001
310001212001212200220121221021
411110201130232311232001
511031343300112024022
6121434020352425441
74633430064552301
oct524413456655601
9101761780817837
1023400537611137
117502126481335
12275b220848281
13100987994546b
145ac84089d601
152a8a7d2ba7c7
hex15485cbb5b81

23400537611137 has 4 divisors (see below), whose sum is σ = 23400552967936. Its totient is φ = 23400522254340.

The previous prime is 23400537611117. The next prime is 23400537611177. The reversal of 23400537611137 is 73111673500432.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23400537611137 - 235 = 23366177872769 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23400537611093 and 23400537611102.

It is not an unprimeable number, because it can be changed into a prime (23400537611117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5105289 + ... + 8536102.

It is an arithmetic number, because the mean of its divisors is an integer number (5850138241984).

Almost surely, 223400537611137 is an apocalyptic number.

It is an amenable number.

23400537611137 is a deficient number, since it is larger than the sum of its proper divisors (15356799).

23400537611137 is a wasteful number, since it uses less digits than its factorization.

23400537611137 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15356798.

The product of its (nonzero) digits is 317520, while the sum is 43.

The spelling of 23400537611137 in words is "twenty-three trillion, four hundred billion, five hundred thirty-seven million, six hundred eleven thousand, one hundred thirty-seven".

Divisors: 1 1715407 13641391 23400537611137