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2340101121 = 323223152083
BaseRepresentation
bin1000101101111011…
…0001110000000001
320001002022110020220
42023132301300001
514243031213441
61024112253253
7111663350151
oct21336616001
96032273226
102340101121
11aa0a20676
12553841229
132b3a75a27
14182b0a761
15da693466
hex8b7b1c01

2340101121 has 16 divisors (see below), whose sum is σ = 3270414336. Its totient is φ = 1485536976.

The previous prime is 2340101081. The next prime is 2340101131. The reversal of 2340101121 is 1211010432.

It is not a de Polignac number, because 2340101121 - 213 = 2340092929 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2340101121.

It is not an unprimeable number, because it can be changed into a prime (2340101131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60655 + ... + 91428.

It is an arithmetic number, because the mean of its divisors is an integer number (204400896).

Almost surely, 22340101121 is an apocalyptic number.

It is an amenable number.

2340101121 is a deficient number, since it is larger than the sum of its proper divisors (930313215).

2340101121 is a wasteful number, since it uses less digits than its factorization.

2340101121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152332.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 2340101121 is about 48374.5916881993. The cubic root of 2340101121 is about 1327.6335178745.

Adding to 2340101121 its reverse (1211010432), we get a palindrome (3551111553).

The spelling of 2340101121 in words is "two billion, three hundred forty million, one hundred one thousand, one hundred twenty-one".

Divisors: 1 3 23 69 223 669 5129 15387 152083 456249 3497909 10493727 33914509 101743527 780033707 2340101121