Base | Representation |
---|---|
bin | 1101100111110000110… |
… | …1010111110110110001 |
3 | 211101000201002010002102 |
4 | 3121330031113312301 |
5 | 12313224100124403 |
6 | 255300443430145 |
7 | 22623016103153 |
oct | 3317415276661 |
9 | 741021063072 |
10 | 234012114353 |
11 | 90275813116 |
12 | 3942a225355 |
13 | 190b4987a24 |
14 | b47d314ad3 |
15 | 6149417b88 |
hex | 367c357db1 |
234012114353 has 4 divisors (see below), whose sum is σ = 234016760688. Its totient is φ = 234007468020.
The previous prime is 234012114317. The next prime is 234012114359. The reversal of 234012114353 is 353411210432.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 234012114353 - 26 = 234012114289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (234012114359) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2246783 + ... + 2348628.
It is an arithmetic number, because the mean of its divisors is an integer number (58504190172).
Almost surely, 2234012114353 is an apocalyptic number.
It is an amenable number.
234012114353 is a deficient number, since it is larger than the sum of its proper divisors (4646335).
234012114353 is an equidigital number, since it uses as much as digits as its factorization.
234012114353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4646334.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 234012114353 its reverse (353411210432), we get a palindrome (587423324785).
The spelling of 234012114353 in words is "two hundred thirty-four billion, twelve million, one hundred fourteen thousand, three hundred fifty-three".
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