Search a number
-
+
234143313003 = 32171530348451
BaseRepresentation
bin1101101000010000000…
…1110110110001101011
3211101100211221200210200
43122010001312301223
512314011142004003
6255321451443243
722626201215415
oct3320401666153
9741324850720
10234143313003
1190332883656
1239466156523
1319105c02c72
14b4929079b5
156155bd16a3
hex3684076c6b

234143313003 has 12 divisors (see below), whose sum is σ = 358101537768. Its totient is φ = 146913451200.

The previous prime is 234143312941. The next prime is 234143313043. The reversal of 234143313003 is 300313341432.

234143313003 is a `hidden beast` number, since 2 + 341 + 4 + 3 + 313 + 0 + 0 + 3 = 666.

It is not a de Polignac number, because 234143313003 - 212 = 234143308907 is a prime.

It is not an unprimeable number, because it can be changed into a prime (234143313043) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 765174073 + ... + 765174378.

It is an arithmetic number, because the mean of its divisors is an integer number (29841794814).

Almost surely, 2234143313003 is an apocalyptic number.

234143313003 is a deficient number, since it is larger than the sum of its proper divisors (123958224765).

234143313003 is a wasteful number, since it uses less digits than its factorization.

234143313003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1530348474 (or 1530348471 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 27.

Adding to 234143313003 its reverse (300313341432), we get a palindrome (534456654435).

The spelling of 234143313003 in words is "two hundred thirty-four billion, one hundred forty-three million, three hundred thirteen thousand, three".

Divisors: 1 3 9 17 51 153 1530348451 4591045353 13773136059 26015923667 78047771001 234143313003